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AD9522-5/PCBZ датащи(PDF) 40 Page - Analog Devices |
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AD9522-5/PCBZ датащи(HTML) 40 Page - Analog Devices |
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40 / 76 page ![]() AD9522-5 Rev. 0 | Page 40 of 76 Table 30. Channel Divider Output Duty Cycle with VCO Divider ≠ 1, Input Duty Cycle Is X% VCO Divider DX Output Duty Cycle N + M + 2 Disable Div DCC = 1 Disable Div DCC = 0 Even Channel divider bypassed 50% 50% Odd = 3 Channel divider bypassed 33.3% (1 + X%)/3 Odd = 5 Channel divider bypassed 40% (2 + X%)/5 Even Even (N + 1)/ (N + M + 2) 50%, requires M = N Even Odd (N + 1)/ (N + M + 2) 50%, requires M = N + 1 Odd = 3 Even (N + 1)/ (N + M + 2) 50%, requires M = N Odd = 3 Odd (N + 1)/ (N + M + 2) (3N + 4 + X%)/(6N + 9), requires M = N + 1 Odd = 5 Even (N + 1)/ (N + M + 2) 50%, requires M = N Odd = 5 Odd (N + 1)/ (N + M + 2) (5N + 7 + X%)/(10N + 15), requires M = N + 1 Table 31. Channel Divider Output Duty Cycle When the VCO Divider Is Enabled and Set to 1 Input Clock Duty Cycle DX Output Duty Cycle N + M + 2 Disable Div DCC = 1 Disable Div DCC = 0 Any Even (N + 1)/ (M + N + 2) 50%, requires M = N 50% Odd (N + 1)/ (M + N + 2) 50%, requires M = N + 1 X% Odd (N + 1)/ (M + N + 2) (N + 1 + X%)/(2 × N + 3), requires M = N + 1 Note that the channel divider must be enabled when the VCO divider = 1. Table 32. Channel Divider Output Duty Cycle When the VCO Divider Is Bypassed Input Clock Duty Cycle DX Output Duty Cycle N + M + 2 Disable Div DCC = 1 Disable Div DCC = 0 Any Channel divider bypassed Same as input duty cycle Same as input duty cycle Any Even (N + 1)/ (M + N + 2) 50%, requires M = N 50% Odd (N + 1)/ (M + N + 2) 50%, requires M = N + 1 X% Odd (N + 1)/ (M + N + 2) (N + 1 + X%)/(2 × N + 3), requires M = N + 1 If the CLK input is routed directly to the output, the duty cycle of the output is the same as the CLK input. Phase Offset or Coarse Time Delay Each channel divider allows for a phase offset, or a coarse time delay, to be programmed by setting register bits (see Table 33). These settings determine the number of cycles (successive rising edges) of the channel divider input frequency by which to offset, or delay, the rising edge of the output of the divider. This delay is with respect to a nondelayed output (that is, with a phase offset of zero). The amount of the delay is set by five bits loaded into the phase offset (PO) register plus the start high (SH) bit for each channel divider. When the start high bit is set, the delay is also affected by the number of low cycles (M) programmed for the divider. It is necessary to use the SYNC function to make phase offsets effective (see the Synchronizing the Outputs—SYNC Function section). Table 33. Setting Phase Offset and Division Divider Start High (SH) Phase Offset (PO) Low Cycles M High Cycles N 0 0x191[4] 0x191[3:0] 0x190[7:4] 0x190[3:0] 1 0x194[4] 0x194[3:0] 0x193[7:4] 0x193[3:0] 2 0x197[4] 0x197[3:0] 0x196[7:4] 0x196[3:0] 3 0x19A[4] 0x19A[3:0] 0x199[7:4] 0x199[3:0] Let Δt = delay (in seconds). Δc = delay (in cycles of clock signal at input to DX). TX = period of the clock signal at the input of the divider, DX (in seconds). Φ = 16 × SH[4] + 8 × PO[3] + 4 × PO[2] + 2 × PO[1] + 1 × PO[0] The channel divide-by is set as N = high cycles and M = low cycles. Case 1 For Φ ≤ 15, Δt = Φ × TX Δc = Δt/TX = Φ Case 2 For Φ ≥ 16, Δt = (Φ − 16 + M + 1) × TX Δc = Δt/TX |
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