HT9580 datasheet(21/63 Pages) HOLTEK

21 / 63 page

HT9580

April 28, 2000

Preliminary

If the internal 2 Mbits mask ROM is placed as

shown in the figure and the software program-

mer obtains a start address from CNS (Taiwan)

code or a GB (China) code, A0~A17. The follow-

ing steps will map from the start address to the

bank point register, then the hardware address

decode circuit will point to the real 2 Mbits

space. (If the internal mask ROM is selected.)

· Step 1

The formula obtains A0~A18 from the re-

ceived GB or CNS code. If it is in the lower 2

Mbits space, A18=0. Otherwise, A18=1 if it is

in reserved space.

· Step 2

Set (BP_MODM1, BP_MODM0)=(0, 1)

· Step 3

Assign correct ²M_BP0²~²M_BP5² as shown:

A13®M_BP0

A14®M_BP1

A15®M_BP2

A16®M_BP3

A17®M_BP4

A18®M_BP5 (the bit will be 0 at this condi-

tion)

· Step 4

Adding $1000 H to A12~A0 to get new HEX

value $B3B2B1B0 H.

· Step 5

The following example will load 32 bytes con-

tinuous (one Chinese word) pattern from the

internal mask ROM and store them to the

start address $C3C2C1C0 H (if absolute index

addressing mode is used).

LDX #00H

LDY #00H

READ:

LDA $B3B2B1B0,X

STA

$C3C2C1C0,Y

INX

INY

CPX #20H

BNZ READ

CNS P a t t e r n

( G B P a t t er n)

( A 18 = "0 ")

Re s e r v e d

( A 18 = "1")

0000 0H

3 F FFF H

4000 0H

7 F FFF H

A12

A11

A10

R A 13

R A 12

A 1 1

A 1 0

A 9A 8A 7A 6A 5A 4A 3A 2A 1

A 0

B 3 ( 0 ,0 ,R A 13 , R A 12 )

B 2 ( A 11, A 10, A 9 , A 8)

B 1 ( A 7, A 6 , A 5, A 4 )

B 0 ( A 3 , A 2 ,A 1,A 0 )

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