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LTC6955 датащи(PDF) 17 Page - Analog Devices

номер детали LTC6955
подробное описание детали  Ultralow Jitter, 7.5GHz 11 Output Fanout Buffer Family
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производитель  AD [Analog Devices]
домашняя страница  http://www.analog.com
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LTC6955
17
Rev 0
For more information www.analog.com
Preliminary Technical Data
Advance Product Information Subject to Change
Rev PrA
In the third scenario, a perfect sine wave input is buffered
by a noiseless amplifier to drive the ADC. Sampling is
performed by a clock signal with added jitter. Note that
as the signal is slewing, the jitter of the clock signal leads
to an uncertainty in the digitized value and an error term
just as in the previous scenario. Again, this error term
degrades the SNR.
A real-world system will have both additive amplifier noise
and sample clock jitter. Once the signal is digitized, deter-
mining the root cause of any SNR degradation – amplifier
noise or sampling clock jitter – is difficult.
Degradation of the SNR due to sample clock jitter only
occurs if the analog input signal is slewing. If the analog
input signal is stationary (DC) then it does not matter
when in time the sampling occurs. Additionally, a faster
slewing input signal yields a greater error (more noise)
than a slower slewing input signal.
Figure 7 demonstrates this effect. Note how much larger
the error term is with the fast slewing signal than with the
slow slewing signal. To maintain the data converter’s SNR
performance, digitization of high input frequency signals
requires a clock with much less jitter than applications
with lower frequency input signals.
It is important to note that the frequency of the analog
input signal determines the sample clock’s jitter require-
ment. The actual sample clock frequency does not matter.
Many ADC applications that under-sample high frequency
signals have especially challenging sample clock jitter
requirements.
The previous discussion was useful for gaining an intui-
tive feel for the SNR degradation due to sampling clock
jitter.
Quantitatively, the actual sample clock jitter requirement
for a given application is calculated as follows:
tJ(TOTAL) =
10
−SNRdB
20
2 •
π • fSIG
(1)
Where fSIG is the highest frequency signal to be digitized
expressed in Hz, SNRdB is the SNR requirement in deci-
bels and tJ(TOTAL) is the total RMS jitter in seconds. The
total jitter is the RMS sum of the ADC’s aperture jitter and
the sample clock jitter calculated as follows:
tJ(TOTAL) = tJ(CLK)
2 + t
J(ADC)
2
(2)
Alternatively, for a given total jitter, the attainable SNR is
calculated as follows:
SNRdB = −20log10 2 • π • fSIG • tJ(TOTAL)
(
)
(3)
These calculations assume a full-scale sine wave input
signal. If the input signal is a complex, modulated signal
with a moderate crest factor, the peak slew rate of the
signal may be lower and the sample clock jitter require-
ment may be relaxed.
Figure 7. Fast and Slow Sine Wave Signals
Sampled with a Jittery Clock
6955 F07
tJ
∆V = VERROR(SLOW)
∆V = VERROR(FAST)
FAST
SINE WAVE
SLOW
SINE WAVE
APPLICATIONS INFORMATION



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