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LTC6955 датащи(PDF) 17 Page - Analog Devices |
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LTC6955 датащи(HTML) 17 Page - Analog Devices |
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17 / 22 page ![]() LTC6955 17 Rev 0 For more information www.analog.com Preliminary Technical Data Advance Product Information Subject to Change Rev PrA In the third scenario, a perfect sine wave input is buffered by a noiseless amplifier to drive the ADC. Sampling is performed by a clock signal with added jitter. Note that as the signal is slewing, the jitter of the clock signal leads to an uncertainty in the digitized value and an error term just as in the previous scenario. Again, this error term degrades the SNR. A real-world system will have both additive amplifier noise and sample clock jitter. Once the signal is digitized, deter- mining the root cause of any SNR degradation – amplifier noise or sampling clock jitter – is difficult. Degradation of the SNR due to sample clock jitter only occurs if the analog input signal is slewing. If the analog input signal is stationary (DC) then it does not matter when in time the sampling occurs. Additionally, a faster slewing input signal yields a greater error (more noise) than a slower slewing input signal. Figure 7 demonstrates this effect. Note how much larger the error term is with the fast slewing signal than with the slow slewing signal. To maintain the data converter’s SNR performance, digitization of high input frequency signals requires a clock with much less jitter than applications with lower frequency input signals. It is important to note that the frequency of the analog input signal determines the sample clock’s jitter require- ment. The actual sample clock frequency does not matter. Many ADC applications that under-sample high frequency signals have especially challenging sample clock jitter requirements. The previous discussion was useful for gaining an intui- tive feel for the SNR degradation due to sampling clock jitter. Quantitatively, the actual sample clock jitter requirement for a given application is calculated as follows: tJ(TOTAL) = 10 −SNRdB 20 2 • π • fSIG (1) Where fSIG is the highest frequency signal to be digitized expressed in Hz, SNRdB is the SNR requirement in deci- bels and tJ(TOTAL) is the total RMS jitter in seconds. The total jitter is the RMS sum of the ADC’s aperture jitter and the sample clock jitter calculated as follows: tJ(TOTAL) = tJ(CLK) 2 + t J(ADC) 2 (2) Alternatively, for a given total jitter, the attainable SNR is calculated as follows: SNRdB = −20log10 2 • π • fSIG • tJ(TOTAL) ( ) (3) These calculations assume a full-scale sine wave input signal. If the input signal is a complex, modulated signal with a moderate crest factor, the peak slew rate of the signal may be lower and the sample clock jitter require- ment may be relaxed. Figure 7. Fast and Slow Sine Wave Signals Sampled with a Jittery Clock 6955 F07 tJ ∆V = VERROR(SLOW) ∆V = VERROR(FAST) FAST SINE WAVE SLOW SINE WAVE APPLICATIONS INFORMATION |
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