PIC18F1220ESLASHSOSQTP datasheet(65/308 Pages) MICROCHIP

65 / 308 page

DS39605F-page 63

PIC18F1220/1320

6.5

Writing to Flash Program Memory

The programming block size is 4 words or 8 bytes.

Word or byte programming is not supported.

Table writes are used internally to load the holding

registers needed to program the Flash memory. There

are 8 holding registers used by the table writes for

programming.

Since the Table Latch (TABLAT) is only a single byte,

the TBLWT instruction must be executed 8 times for

each programming operation. All of the table write

operations will essentially be short writes, because only

the holding registers are written. At the end of updating

8 registers, the EECON1 register must be written to, to

start the programming operation with a long write.

The long write is necessary for programming the

internal Flash. Instruction execution is halted while in a

long write cycle. The long write will be terminated by

the internal programming timer.

FIGURE 6-5:

TABLE WRITES TO FLASH PROGRAM MEMORY

6.5.1

FLASH PROGRAM MEMORY WRITE

SEQUENCE

The sequence of events for programming an internal

program memory location should be:

Read 64 bytes into RAM.

Update data values in RAM as necessary.

Load Table Pointer with address being erased.

Do the row erase procedure (see Section 6.4.1

“Flash Program Memory Erase Sequence”).

Load Table Pointer with address of first byte

being written.

Write the first 8 bytes into the holding registers

with auto-increment.

Set the EECON1 register for the write operation:

• set EEPGD bit to point to program memory;

• clear the CFGS bit to access program

memory;

• set WREN bit to enable byte writes.

Disable interrupts.

Write 55h to EECON2.

10. Write AAh to EECON2.

11. Set the WR bit. This will begin the write cycle.

12. The CPU will stall for duration of the write (about

2 ms using internal timer).

13. Execute a NOP.

14. Re-enable interrupts.

15. Repeat steps 6-14 seven times to write

64 bytes.

16. Verify the memory (table read).

This procedure will require about 18 ms to update one

row of 64 bytes of memory. An example of the required

code is given in Example 6-3.

Holding Register

TABLAT

Holding Register

TBLPTR = xxxxx7

Holding Register

TBLPTR = xxxxx1

Holding Register

TBLPTR = xxxxx0

Write Register

TBLPTR = xxxxx2

Program Memory

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