ATmega169P datasheet(186/393 Pages) ATMEL

186 / 393 page

186

8018N–AVR–08/09

ATmega169P

Figure 19-6. Sampling of Data and Parity Bit

The decision of the logic level of the received bit is taken by doing a majority voting of the logic

value to the three samples in the center of the received bit. The center samples are emphasized

on the figure by having the sample number inside boxes. The majority voting process is done as

follows: If two or all three samples have high levels, the received bit is registered to be a logic 1.

If two or all three samples have low levels, the received bit is registered to be a logic 0. This

majority voting process acts as a low pass filter for the incoming signal on the RxD pin. The

recovery process is then repeated until a complete frame is received. Including the first stop bit.

Note that the Receiver only uses the first stop bit of a frame.

Figure 19-7 on page 186 shows the sampling of the stop bit and the earliest possible beginning

of the start bit of the next frame.

Figure 19-7. Stop Bit Sampling and Next Start Bit Sampling

The same majority voting is done to the stop bit as done for the other bits in the frame. If the stop

bit is registered to have a logic 0 value, the Frame Error (FEn) Flag will be set.

A new high to low transition indicating the start bit of a new frame can come right after the last of

the bits used for majority voting. For Normal Speed mode, the first low level sample can be at

point marked (A) in Figure 19-7 on page 186. For Double Speed mode the first low level must be

delayed to (B). (C) marks a stop bit of full length. The early start bit detection influences the

operational range of the Receiver.

19.8.3

Asynchronous Operational Range

The operational range of the Receiver is dependent on the mismatch between the received bit

rate and the internally generated baud rate. If the Transmitter is sending frames at too fast or too

slow bit rates, or the internally generated baud rate of the Receiver does not have a similar (see

Table 19-2 on page 187) base frequency, the Receiver will not be able to synchronize the

frames to the start bit.

BIT n

123

678

RxD

Sample

(U2X = 0)

Sample

(U2X = 1)

0/1

STOP 1

123

0/1

RxD

Sample

(U2X = 0)

Sample

(U2X = 1)

(A)

(B)

(C)

ATmega169P датащи(PDF) 186 Page - ATMEL Corporation

ATmega169P датащи(HTML) 186 Page - ATMEL Corporation

Html Pages

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 ...More

датащи скачать

ссылки URL