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AN2644 датащи(PDF) 32 Page - STMicroelectronics |
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AN2644 датащи(HTML) 32 Page - STMicroelectronics |
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32 / 64 page ![]() The LLC resonant half-bridge converter AN2644 32/64 (plus the contribution from LL2, not shown here). This phase ends when Q2 is switched on at t=t3. d) t3 → t4. Q1 is OFF and Q2 is ON. At t=t3 IR is diverted from DQ2 to the RDS(on) of Q2, so that no significant energy is lost during the turn-on transient. Note that now the operating point of Q2 is in the third quadrant, current is flowing from the source to drain. D2 keeps on conducting and the voltage across Lp is -a·Vout, so that Lp is not participating in resonance and Cr is resonating with Ls only. IR is a portion of a sinusoid having a frequency f = fR1. This phase ends when IR=0 at t=t4. Figure 21. Operation below resonance (fR2 < f < fR1, R>Rcrit): main waveforms in DCMB2 operation e) t4 → t5. Q1 is OFF and Q2 is ON. The tank circuit current, which is zero at t=t4 becomes negative. D1 is nonconducting and its reverse voltage is approximately 2·Vout (plus the contribution from LL2, here not shown). Lp's current has a negative slope, so the voltage across Lp must be negative. Since the diode D2 is conducting this voltage will be equal to -a·Vout. Lp, then, is not participating in resonance, Cr is resonating with Ls only and IR is a portion of a sinusoid having a frequency f = fR1. During this phase, which ends when IR equals I(Lp) and, thereby, I(D2) is zero at t=t15. IR reaches its minimum value, after that it starts increasing. f) t5 → t6. This phase mirrors (t1, t2). At t=t5 I(D2) becomes zero and IR equals I(Lp), that is before the conduction time of Q1 ends. Both D1 and D2 are nonconducting and Lp, no longer shunted by the load reflected to the primary side, goes effectively in series to Ls and participates to resonance. IR is now a portion of a sinusoid having a frequency f = fR2. This phase ends when Q2 is switched off at t=t6. I(D2) = D2 current V(D2) = D2 anode voltage I(Q2) = Q2 current I(Lp) = Lp (magnetizing) current Vc = Resonant capacitor voltage LVG = Q2 gate I(D1) = D1 current V(D1) = D1 anode voltage I(Q1) = Q1 current IR = Tank circuit’s current VHB = Node HB voltage HVG= Q1 gate t 0 t 1 t 3 t 4 t 2 Q1 OFF Q2 ON Q1 ON Q2 OFF t 5 t 7 t 6 t 8 Q1 ON Q2 OFF I(D2) = D2 current V(D2) = D2 anode voltage I(Q2) = Q2 current I(Lp) = Lp (magnetizing) current Vc = Resonant capacitor voltage LVG = Q2 gate I(D1) = D1 current V(D1) = D1 anode voltage I(Q1) = Q1 current IR = Tank circuit’s current VHB = Node HB voltage HVG= Q1 gate t 0 t 1 t 3 t 4 t 2 Q1 OFF Q2 ON Q1 ON Q2 OFF t 5 t 7 t 6 t 8 Q1 ON Q2 OFF I(D2) = D2 current V(D2) = D2 anode voltage I(Q2) = Q2 current I(Lp) = Lp (magnetizing) current Vc = Resonant capacitor voltage LVG = Q2 gate I(D1) = D1 current V(D1) = D1 anode voltage I(Q1) = Q1 current IR = Tank circuit’s current VHB = Node HB voltage HVG= Q1 gate I(D2) = D2 current V(D2) = D2 anode voltage I(Q2) = Q2 current I(Lp) = Lp (magnetizing) current Vc = Resonant capacitor voltage LVG = Q2 gate I(D1) = D1 current V(D1) = D1 anode voltage I(Q1) = Q1 current IR = Tank circuit’s current VHB = Node HB voltage HVG= Q1 gate t 0 t 0 t 1 t 1 t 3 t 3 t 4 t 4 t 2 t 2 Q1 OFF Q2 ON Q1 ON Q2 OFF t 5 t 5 t 7 t 7 t 6 t 6 t 8 t 8 Q1 ON Q2 OFF |
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