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ADA4945-1ACPZ-R2 датащи(PDF) 38 Page - Analog Devices |
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ADA4945-1ACPZ-R2 датащи(HTML) 38 Page - Analog Devices |
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38 / 44 page ![]() ADA4945-1 Data Sheet Rev. 0 | Page 38 of 44 IMPACT OF MISMATCHES IN THE FEEDBACK NETWORKS Even if the external feedback networks (RF/RG) are mismatched, the internal common-mode feedback loop still forces the outputs to remain balanced. The amplitudes of the signals at each output remain equal and 180° out of phase. The input-to-output, differential mode gain varies proportionately to the feedback mismatch, but the output balance is unaffected. As well as causing a noise contribution from VOCM, ratio matching errors in the external resistors result in a degradation of the ability of the circuit to reject input common-mode signals, similar to a four resistors difference amplifier made from a conventional op amp. In addition, if the dc levels of the input and output common- mode voltages are different, matching errors result in a small differential mode, output offset voltage. When G = 1, with a ground referenced input signal and the output common-mode level set to 2.5 V, an output offset of as much as 25 mV (1% of the difference in common-mode levels) can result if 1% tolerance resistors are used. Resistors of 1% tolerance result in a worst case input CMRR of about 40 dB, a worst case differential mode output offset of 25 mV due to the 2.5 V level shift, and no significant degradation in output balance error. CALCULATING THE INPUT IMPEDANCE OF AN APPLICATION CIRCUIT The effective input impedance depends on whether the signal source is single-ended or differential. For a balanced differential input signal, as shown in Figure 103, the input impedance (RIN,dm) between the inputs (+DIN and −DIN) is RIN, dm = 2 × RG. +VS ADA4945-1 +IN –IN RF RF +DIN –DIN VOCM RG RG VOUT, dm Figure 103. ADA4945-1 Configured for Balanced (Differential) Inputs For an unbalanced single-ended input signal, as shown in Figure 104, the input impedance is RIN,SE = RG1 ) 1 ( + + β2 β1 β2 β1 where: β1 = F1 G1 G1 R R R + β2 = 2 2 F G2 G R R R + ADA4945-1 RL VOUT, dm +VS –VS RG1 RG2 RF2 RF1 VOCM RIN, SE Figure 104. ADA4945-1 with Unbalanced (Single-Ended) Input For a balanced system where RG1 = RG2 = RG and RF1 = RF2 = RF, the equations simplify to + − = + = = ) 2( 1 F G F G IN,SE F G G R R R R R and R R R β2 β1 The input impedance of the circuit is effectively higher than it would be for a conventional op amp connected as an inverter because a fraction of the differential output voltage appears at the inputs as a common-mode signal, partially bootstrapping the voltage across the RG1 input resistor. |
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