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LM2647 датащи(PDF) 22 Page - National Semiconductor (TI) |
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LM2647 датащи(HTML) 22 Page - National Semiconductor (TI) |
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22 / 25 page ![]() Application Information (Continued) MODULATOR GAIN/COMPENSATION The modulator gain is plotted out for various typical values of components in Typical Performance characteristics. The curves were based on the following information. The plant/ modulator gain ‘G’ is: where Ro is the load resistance,s=j ω, and A1 = LC*(Ro + esr) A2={L + R PC(Ro + esr) + Ro*esr*C} A3=R o +RP Here esr is the Equivalent Series Resistance of the output capacitor, Ro is the load resistance, C is the output capaci- tance, L is the inductance, and R P is the resistance of the power stage (Rds+ DCR etc, typically about 40m Ω). V RAMP is about 1.6V for the LM2647. The unity gain bandwidth of the error amplifier is taken as 6.5MHz. Let us assume Type 3 compensation Figure 15. The design procedure is summarized in Table 2. TABLE 2. Summary of Compensation Design Procedure fp1 fz1 fz2 fp2 fp3 Type 3 (C1) R2, C2 R1sR3, C3 R2, C1sC2 C3, R3 Resonant frequency f = 1⁄2 πRC, ’s’ stands for series combination. TABLE 3. C1 C2 C3 R2 R3 A is a factor to shift entire Gain up or down to acheive good crossover frequency and gain. Typically set A = 0.2 here. TABLE 4. fp1 fz1 fz2 fp2 fp3 (0) fdp fdb fesr fsw/2 Resonant frequency f = 1⁄2 πRC, ’s’ stands for series combination. A short explanation on Table 2 follows. For example from the table it can be seen that the second zero is created by the series combination of R1 and R3 resonating with C3. So the frequency of this zero is at 1/2 π(R1+R3)*C3. The solution for calculating the component values follows. For example, C3 is set as But where should the designer position the poles and zeroes of the error amplifier, taking into account the modulator gain, so as to achieve good closed loop characteristics? A typical scenario is also provided in Table 4. For example it suggests that both the first and second zeroes should be positioned at the point where double pole (fdb) of the output LC filter is. This double pole is known to occur at about. Similarly, the esr zero occurs at fesr which is at where C is the output capacitance Thus all the components can be calculated easily EVALUATION BOARD DETAILS The Bill of Materials is now provided for the LM2647 Evalu- ation board. The schematic is the Typical Application circuit. See Layout Guidelines for more guidance on preferred lay- out practices and also refer to Application Note AN-1229. Note that a dual FET pack has been chosen for the Evalu- ation Board. The Evaluation board has two outputs V O1 = 5V and VO2 = 3.3V as discussed under Setting Output Voltage section. The rated load on each output is 2A continuous, and 3A peak. A minimum load of 0.1mA should be maintained on each out- put in SKIP mode, to ensure regulation. 20056348 FIGURE 15. Type 3 Compensation www.national.com 22 |
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