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LM2647 датащи(PDF) 22 Page - National Semiconductor (TI)

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номер детали LM2647
подробное описание детали  Dual Synchronous Buck Regulator Controller
PDF  25 Pages
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Application Information (Continued)
MODULATOR GAIN/COMPENSATION
The modulator gain is plotted out for various typical values of
components in Typical Performance characteristics. The
curves were based on the following information. The plant/
modulator gain ‘G’ is:
where Ro is the load resistance,s=j
ω, and
A1 = LC*(Ro + esr)
A2={L + R
PC(Ro + esr) + Ro*esr*C}
A3=R
o +RP
Here esr is the Equivalent Series Resistance of the output
capacitor, Ro is the load resistance, C is the output capaci-
tance, L is the inductance, and R
P is the resistance of the
power stage (Rds+ DCR etc, typically about 40m
Ω). V
RAMP
is about 1.6V for the LM2647. The unity gain bandwidth of
the error amplifier is taken as 6.5MHz.
Let us assume Type 3 compensation Figure 15.
The design procedure is summarized in Table 2.
TABLE 2. Summary of Compensation Design Procedure
fp1
fz1
fz2
fp2
fp3
Type 3
(C1)
R2, C2
R1sR3, C3
R2, C1sC2
C3, R3
Resonant frequency f = 12
πRC, ’s’ stands for series combination.
TABLE 3.
C1
C2
C3
R2
R3
A is a factor to shift entire Gain up or down to acheive good crossover frequency and gain. Typically set A = 0.2 here.
TABLE 4.
fp1
fz1
fz2
fp2
fp3
(0)
fdp
fdb
fesr
fsw/2
Resonant frequency f = 12
πRC, ’s’ stands for series combination.
A short explanation on Table 2 follows. For example from the
table it can be seen that the second zero is created by the
series combination of R1 and R3 resonating with C3. So the
frequency of this zero is at 1/2
π(R1+R3)*C3. The solution for
calculating the component values follows. For example, C3
is set as
But where should the designer position the poles and zeroes
of the error amplifier, taking into account the modulator gain,
so as to achieve good closed loop characteristics? A typical
scenario is also provided in Table 4. For example it suggests
that both the first and second zeroes should be positioned at
the point where double pole (fdb) of the output LC filter is.
This double pole is known to occur at about.
Similarly, the esr zero occurs at fesr which is at
where C is the output capacitance
Thus all the components can be calculated easily
EVALUATION BOARD DETAILS
The Bill of Materials is now provided for the LM2647 Evalu-
ation board. The schematic is the Typical Application circuit.
See Layout Guidelines for more guidance on preferred lay-
out practices and also refer to Application Note AN-1229.
Note that a dual FET pack has been chosen for the Evalu-
ation Board.
The Evaluation board has two outputs V
O1 = 5V and VO2 =
3.3V as discussed under Setting Output Voltage section. The
rated load on each output is 2A continuous, and 3A peak. A
minimum load of 0.1mA should be maintained on each out-
put in SKIP mode, to ensure regulation.
20056348
FIGURE 15. Type 3 Compensation
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