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LM27213MTDX/NOPB.B датащи(PDF) 21 Page - Texas Instruments

номер детали LM27213MTDX/NOPB.B
подробное описание детали  LM27213 Single Phase Hysteretic Buck Controller
PDF  38 Pages
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производитель  TI2 [Texas Instruments]
домашняя страница  https://www.ti.com
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LM27213MTDX/NOPB.B датащи(HTML) 21 Page - Texas Instruments

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LM27213
www.ti.com
SNVS377A – FEBRUARY 2006 – REVISED MARCH 2013
Figure 22. RMS Input Ripple Current as a Percentage of DC Output Current
So for a design that must operate at a steady state load current of 12A, with 1.4V out and 8V in, the RMS input
ripple current would be about 37% of 12A or 4.4A RMS. A sufficient number of capacitors must be connected in
parallel to handle this current. For capacitors rated at 1.5A each, a minimum of 3 would be required. If it’s
desired to add enough bulk capacitance to control the input’s low frequency ripple voltage, the characteristic
impedance of the input power source must be well understood.
Bypassing Considerations
The LM27213 should have its supply pin (24) well bypassed. Generally a 1µF capacitor connected between the
Vdd pin and the SGND pin (23), should be adequate. It’s a good idea to add a resistor of about 10
Ω in series
with the input source to provide some decoupling from noise on the 5V rail. The LM27213’s own gate drive pulse
currents can corrupt the 5V rail enough to cause problems without this filter. There also needs to be a 1µF or
larger ceramic capacitor connected between the driver supply pin PVDD (48) and PGND (45). The bypass
capacitors should be located very close to the pins to provide a low inductance path. This is particularly important
for the PVDD bypass. This capacitor must supply all of the low-side gate drive pulse currents as well as the
charging current for the high-side bootstrap capacitor. It’s also a good idea to install a 0.1µF capacitor between
the VREF pin (11) and SGND. In addition, there should be small filter capacitors connected between the ILIM
and ILIMREF pins and the CMP and CMPREF pins. Typically, a 1200pF capacitor will prove adequate for this
purpose.
Current Sense Resistor
The maximum value allowed for the current sense resistor is a value equal to the desired load line slope.
Increasing beyond this value will make the load line excessively steep with no way to reduce the slope. Lower
values are permissible and values as low as 1m
Ω have been used successfully. The regulator will have a
tendency to exhibit excessive amounts of pulse jitter if the sense resistor is too small since the current sense
signal is reduced as well. One way to mitigate this problem is to add a little filtering to the load line setting
resistor R2 in Figure 21. A typical time constant to shoot for is approximately 500ns. So for R2 = 100
Ω,
something around a 4700pF capacitor should prove helpful. If this capacitor is made too large the result will be
large overshoot and undershoot in the response to load transients. See the section below on load line setting for
more information about choosing these resistors.
Load Line Setting Resistors
Resistors R1, R2, and the current sense resistor (see Figure 20) are used to control the slope of the load line. In
the simplest configuration R1 = 0 ohms and R2 is omitted. In this case the load line is nominally equal to the
current sense resistor value. For relatively low current designs this configuration can work acceptably well. At
higher current levels the DC drop across the power planes may well contribute an excessive error since the
distribution path between the sense resistor and the load is effectively in series with the current sense resistor,
and therefore, will steepen the load line. For designs with relatively steep load lines (3 m
Ω) the power dissipation
is also excessive at high currents. The solution is to lower the sense resistor value and add the R1, R2 divider to
synthesize a steeper slope. The load line is calculated from:
LL = Rs x (1+R1/R2)
(16)
Copyright © 2006–2013, Texas Instruments Incorporated
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