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LT1374CS8 датащи(PDF) 27 Page - Linear Technology |
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LT1374CS8 датащи(HTML) 27 Page - Linear Technology |
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27 / 32 page ![]() 27 LT1374 1374fb APPLICATIONS INFORMATION This says that discontinuous mode can be used and the minimum inductor needed is found from: LH MIN = ()( ) () = 25 1 500 10 4 5 1 3 2 •. µ In practice, the inductor should be increased by about 30% over the calculated minimum to handle losses and varia- tions in value. This suggests a minimum inductor of 1.3 µH for this application, but looking at the ripple voltage chart shows that output ripple voltage could be reduced by a fac- tor of two by using a 15 µHinductor.Thereisnoruleofthumb here to make a final decision. If modest ripple is needed and the larger inductor does the trick, go for it. If ripple is non- critical use the smaller inductor. If ripple is extremely criti- cal, a second filter may have to be added in any case, and the lower value of inductance can be used. Keep in mind that the output capacitor is the other critical factor in deter- mining output ripple voltage. Ripple shown on the graph (Figure 16) is with two parallel capacitor’s ESR of 0.1 Ω.This is reasonable for AVX type TPS “D” or “E” size surface mount solid tantalum capacitors, but the final capacitor chosen must be looked at carefully for ESR characteristics. Ripple Current in the Input and Output Capacitors Positive-to-negative converters have high ripple current in both the input and output capacitors. For long capacitor lifetime, the RMS value of this current must be less than the high frequency ripple current rating of the capacitor. The following formula will give an approximate value for RMS ripple current. This formula assumes continuous mode and large inductor value. Small inductors will give somewhat higher ripple current, especially in discontinu- ous mode. The exact formulas are very complex and appear in Application Note 44, pages 30 and 31. For our purposes here I have simply added a fudge factor (ff). The value for ff is about 1.2 for higher load currents and L ≥10µH. It increases to about 2.0 for smaller inductors at lower load currents. Capacitor ff I V V OUT OUT IN IRMS = ()( ) ff = Fudge factor (1.2 to 2.0) Diode Current Average diode current is equal to load current. Peak diode current will be considerably higher. Peak diode current: Continuous I VV V VV Lf V V Discontinuous V Lf OUT IN OUT IN IN OUT IN OUT OUT Mode Mode = 2IOUT = + () + ()( ) ()( ) + () ()( ) ()( ) 2 Keep in mind that during start-up and output overloads, average diode current may be much higher than with normal loads. Care should be used if diodes rated less than 3A are used, especially if continuous overload conditions must be tolerated. |
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