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LT8607 датащи(PDF) 14 Page - Analog Devices |
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LT8607 датащи(HTML) 14 Page - Analog Devices |
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14 / 24 page ![]() LT8607/LT8607B 14 Rev. D For more information www.analog.com APPLICATIONS INFORMATION Inductor Selection and Maximum Output Current The LT8607 is designed to minimize solution size by allowing the inductor to be chosen based on the output load requirements of the application. During overload or short circuit conditions the LT8607 safely tolerates opera- tion with a saturated inductor through the use of a high speed peak-current mode architecture. A good first choice for the inductor value is: L = VOUT + VSW(BOT) fSW • 2 where fSW is the switching frequency in MHz, VOUT is the output voltage, VSW(BOT) is the bottom switch drop (~0.125V) and L is the inductor value in µH. To avoid overheating and poor efficiency, an inductor must be chosen with an RMS current rating that is greater than the maximum expected output load of the applica- tion. In addition, the saturation current (typically labeled ISAT) rating of the inductor must be higher than the load current plus 1/2 of in inductor ripple current: IL(PEAK) =ILOAD(MAX) + 1 2 ΔL where ∆IL is the inductor ripple current as calculated sev- eral paragraphs below and ILOAD(MAX) is the maximum output load for a given application. As a quick example, an application requiring 0.25A output should use an inductor with an RMS rating of greater than 0.5A and an ISAT of greater than 0.7A. To keep the efficiency high, the series resistance (DCR) should be less than 0.04Ω, and the core material should be intended for high frequency applications. The LT8607 limits the peak switch current in order to protect the switches and the system from overload faults. The top switch current limit (ILIM) is at least 1.2A at low duty cycles and decreases linearly to at least 0.9A at D = 0.8. The inductor value must then be sufficient to supply the desired maximum output current (IOUT(MAX)), which is a function of the switch current limit (ILIM) and the ripple current: IOUT(MAX) =ILIM – ΔIL 2 The peak-to-peak ripple current in the inductor can be calculated as follows: ΔIL = VOUT L • fSW 1– VOUT VIN(MAX) ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ where fSW is the switching frequency of the LT8607, and L is the value of the inductor. Therefore, the maximum output current that the LT8607 will deliver depends on the switch current limit, the inductor value, and the input and output voltages. The inductor value may have to be increased if the inductor ripple current does not allow sufficient maximum output current (IOUT(MAX)) given the switching frequency, and maximum input voltage used in the desired application. The optimum inductor for a given application may differ from the one indicated by this design guide. A larger value inductor provides a higher maximum load current and reduces the output voltage ripple. For applications requir- ing smaller load currents, the value of the inductor may be lower and the LT8607 may operate with higher ripple current. This allows use of a physically smaller inductor, or one with a lower DCR resulting in higher efficiency. Be aware that low inductance may result in discontinuous mode operation, which further reduces maximum load current. For more information about maximum output current and discontinuous operation, see Analog Devices Application Note 44. Finally, for duty cycles greater than 50% (VOUT/VIN > 0.5), a minimum inductance is required to avoid sub-harmonic oscillation. See Analog Devices Application Note 19. Input Capacitor Bypass the input of the LT8607 circuit with a ceramic capacitor of X7R or X5R type. Y5V types have poor per- formance over temperature and applied voltage, and should not be used. A 4.7µF to 10µF ceramic capacitor is adequate to bypass the LT8607 and will easily handle the ripple current. Note that larger input capacitance is required when a lower switching frequency is used. If the input power source has high impedance, or there is |
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