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OPA835 датащи(PDF) 11 Page - Texas Instruments |
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OPA835 датащи(HTML) 11 Page - Texas Instruments |
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11 / 21 page ![]() + ± RF ½ OPA2834 Signal and bias to next stage 2.5 V GVSIG 2.5 V VSIG 5 V RO VOUT Signal and bias from previous stage RG C 2.5 V REF 5 V R1 RG ¶ + ± 5 V RF ½ O PA283 4 Sign al and bias to next sta ge 2.5 V GVSIG 2.5 V VSIG 5 V RO VOUT R1 RG ´ Sign al and bias from previou s stag e 11 OPA2834 www.ti.com SBOS973 – JUNE 2019 Product Folder Links: OPA2834 Submit Documentation Feedback Copyright © 2019, Texas Instruments Incorporated Device Functional Modes (continued) Figure 9. Noninverting Single Supply With Resistors Figure 10 shows a typical inverting-amplifier circuit. With a 5-V single-supply, a mid-supply reference generator is needed to bias the positive side through R1. To cancel the voltage offset that is otherwise caused by the input bias currents, R1 is selected to be equal to RF in parallel with RG. For example, if a gain of –2 is required and RF = 3.6 kΩ, select RG = 1.8 kΩ to set the gain and R1 = 1.2 kΩ for bias current cancellation. The value for C is dependent on the reference, but TI recommends a value of at least 0.1 µF to limit noise into the op amp. Figure 10. Inverting Single Supply With Reference Figure 11 illustrates a similar inverting single-supply scenario with the reference generator replaced by the Thevenin equivalent using resistors and the positive supply. R1 and R2 form a resistor divider from the 5-V supply and are used to bias the positive side. To cancel the voltage offset that is otherwise caused by the input bias currents, set the parallel sum of R1 and R2 equal to the parallel sum of RF and RG. C must be added to limit the coupling of noise into the positive input. For example, if a gain of –2 is required and RF = 3.6 kΩ, select RG = 1.8 kΩ to set the gain. R1 = R2 = 2.4 kΩ for the mid-supply voltage bias and for op-amp input-bias current cancellation. A good value for C is 0.1 µF. The resistor divider costs less than the 2.5-V reference in Figure 11 but can increase the current from the 5-V supply. |
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