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PM2102DPD датащи(PDF) 3 Page - Sames

номер детали PM2102DPD
подробное описание детали  Energy Meter Evaluation Module
PDF  16 Pages
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производитель  SAMES [Sames]
домашняя страница  http://www.sames.co.za
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PM2102DPD датащи(HTML) 3 Page - Sames

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PM2102DPD
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PRELIMINARY
Figure 4: Current sensing using a CT
Figure 5: Current sensing using a shunt
Figure 3: Voltage divider circuit
NEUTRAL
LIVE IN
R1
R2
R3
R15
R11
R12
C7
IVP
GND
P1
J16
RA
RB
R1 = R3 = 82k
and
R2 = R15 = 100 k .
Resistors R6 and R7 (figure 4 and figure 5) define the current at
the current sense inputs of the SA2102D. The PM2102DPD
module uses a 625µ
shunt.
At I
(80A) the voltage drop
across the shunt will be 50mV. To ensure proper current
sensing it is advisable to use a shunt that will give a voltage
drop of at least 20mV at I
. The resistor values are calculated
for an input of 16µA
on the current sense inputs at I
(see
Figure 5). The design equation is as follows:
R6 = R7 = (I / 16µA) x R
/ 2
I = Line current
R
= Shunt value
Also see the section on
.
Provision is made for the use of either a Current Transformer
(CT) or a Shunt on the application module. The module is by
default setup for a shunt, which must be removed if a CT is
chosen as the sensing device. When using
a CT, the
terminating resistor (R16), phase compensation capacitor (C7)
and jumper (J5) must be inserted. The jumper references one
side of the CT to ground for sensing. The current sensing
resistors (R6 and R7) must be changed according to the
equation stated below (see Figure 4):
R6 = R7 = (I / 2500 / 16µA) x R
/ 2
I = Line current
CT ratio = 1:2500
W
W
W
Current Sense Input
SETUP EXAMPLES
Sensing Method (CT or SHUNT)
ma
x
ma
x
RM S
m a
x
LSH
terminating
L
SH
L
L
The capacitor C7 is inserted to correct or compensate for the
phase shift caused by the current transformer. The following
equationshows how to calculate the capacitor value for a
phase shift of 0.18 degrees.
C = 1/ (2 x x Mains frequency x R12 x tan (Phase shift angle))
Also see the section on
.
A CT with a low phase shift and a ratio of 1:2500 is
recommended for optimum module performance.
p
C = 1/ (2 x x 50 x 1M x tan (0.18 degrees))
C = 1.013µF
p
SETUP EXAMPLES
CT
LIVE IN
LIVE OUT
R6
R7
CT +
CT-
R16
GND
J5
LIVE IN
LIVE OUT
Shunt
R6
R7
IIN
IIP



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