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AN2986 датащи(PDF) 12 Page - STMicroelectronics

номер детали AN2986
подробное описание детали  This document focuses on the calculation
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AN2986 датащи(HTML) 12 Page - STMicroelectronics

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Gate current variation
AN2986
12/18
Doc ID 15727 Rev 1
2.3
Maximum current calculation
The maximum current that the MCU can handle is based on the following opposite
conditions:
maximum supply voltage (VDDmax),
minimum voltage drop of the gate junction (VGTmin),
minimum gate resistor (0.99 x RG),
minimum output low voltage (VOLmin).
Equation 7
As previously stated, a load RMS current of 1 A for Z0103 and 0.8 A for ACS108-6T is used.
Z01’s minimum VGT is then close to –0.1 V at 1.44 A peak load current in positive half-wave
and for a 125 °C junction temperature (worst case).
ACS108’s minimum VGT is close to 0.6 V for 1.15 A peak load current and for a 125 °C
junction temperature (worst case).
Two examples are shown. The same components are used as those given in Section 1.2.2.
Example 5: MCU: STM8S with ACS108 -6T for power supply 5 V ±10%
Specified values:
RG = 180 Ω, VDD = 5 V, VGT min (0.8 A) = 0.6 V
Calculated values:
VDDmax = 1.1 x 5 V = 5.5 V,
VOLmin IGT = 20 mA) = 0.8 V
IGmax is then given by:
Equation 8
This result exceeds the maximum MCU current capability for one high-sink I/O port. This
IGmax current can be sunk with 2 I/O ports in parallel. Estimation of VOLmin has been
provided for four high-sink I/O ports sinking at the same time 10 mA. VGTmin depends on
load current. A lower load current means higher VGTmin and therefore lower IGmax.
Example 6: STM32 + Z0103 for 3.3 V ±5%
Specified values:
RG = 300 Ω, VDD = 3.3 V, VGT min = –0.1 V
Calculated values:
VDD max = 1.05 x 3.3 V = 3.47 V
VOLmin (IGT = 8 mA) = 0.4 V
IG max is then given by:
Equation 9
I
Gma x
V
DDm ax
V
GTmin
V
OLm in
0.99
R
G
×
------------------------------------------------------------------------
<
I
Gm ax
5.5
0.6
0.8
0.99
180
×
-------------------------------------
23.2mA
=
<
I
Gmax
3.47
0.1
()
0.4
0.99
300
×
------------------------------------------------
10.7mA
=
<



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