| поискавой системы для электроныых деталей |
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082-8003-404 датащи(PDF) 13 Page - Magnetrol International, Inc. |
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082-8003-404 датащи(HTML) 13 Page - Magnetrol International, Inc. |
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13 / 24 page ![]() 50-613 Kotron Series 82 CE RF Level Transmitter 10 7. If 20 mA cannot be reached, individually close Span Coarse DIP switches (in sequence), #1, #2, and #3, until the loop current is close to (and not less than), 20 mA. (ONLY ONE SWITCH POSITION SHOULD BE CLOSED AT A TIME—THE OTHER TWO POSITIONS MUST REMAIN OPEN). 8. Turn the Span Fine potentiometer counterclockwise until the loop current is exactly 20.00 mA. If 20 mA cannot be reached, repeat Step 6. Calibration is now complete. 1.7.2 Calibration Procedure B 1. Move the media level in the vessel to the lowest level you can set. 2. To determine the correct output level at this point, use the following formula: 3. Turn the Zero Coarse potentiometer counterclockwise until the loop output is between L1mA and L1mA + 0.5 mA. 4. If the loop current output cannot be decreased to at least L1mA + 0.5 mA, turn the Zero Coarse potentiometer fully clockwise, close Zero Coarse DIP switch positions #2 and #3 sequentially (ONLY ONE SWITCH POSITION SHOULD BE CLOSED AT A TIME—THE OTHER TWO POSITIONS MUST REMAIN OPEN). Repeat Step 3. See Figure 10. 5. Turn potentiometer Zero Fine counterclockwise until the loop output reads exactly L1mA. 6. Move the media level in the vessel to the highest level you can set. 7. To determine the correct output level at this point, use the following formula: 8. Turn the Span Fine potentiometer counterclockwise until the loop current reaches the desired value calculated (L2mA) in Step 7. 9. If the desired value cannot be obtained, individually close the Span Coarse DIP switches #1, #2, and #3, until the loop current is as close to (and not less than), L2mA. (ONLY ONE SWITCH POSITION SHOULD BE CLOSED AT A TIME—THE OTHER TWO POSI- TIONS MUST REMAIN OPEN). 10. Turn the Span Fine potentiometer counterclockwise until the loop current is exactly L2mA. Calibration is now complete. L2mA = ( (L2 - L0) x 16) + 4 (L3 - L0) L1mA = ( (L1 - L0) x 16) + 4 (L3 - L0) |
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