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SC417 датащи(PDF) 25 Page - Semtech Corporation |
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SC417 датащи(HTML) 25 Page - Semtech Corporation |
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25 / 30 page ![]() SC417/SC427 25 Applications Information (continued) One simple way to solve this problem is to add trace resis- tance in the high current output path. A side effect of adding trace resistance is a decrease in load regulation. ESR Requirements A minimum ESR is required for two reasons. One reason is to generate enough output ripple voltage to provide 10mVp-p at the FB pin (after the resistor divider) to avoid double-pulsing. The second reason is to prevent instability due to insuffi- cient ESR. The on-time control regulates the valley of the output ripple voltage. This ripple voltage is the sum of the two voltages. One is the ripple generated by the ESR, the other is the ripple due to capacitive charging and dis- charging during the switching cycle. For most applica- tions the minimum ESR ripple voltage is dominated by the output capacitors, typically SP or POSCAP devices. For stability the ESR zero of the output capacitor should be lower than approximately one-third the switching fre- quency. The formula for minimum ESR is shown by the following equation. sw OUT MIN f C 2 3 SR E Using Ceramic Output Capacitors For applications using ceramic output capacitors, the ESR is normally too small to meet the above ESR criteria. In these applications it is necessary to add a small virtual ESR network composed of two capacitors and one resistor, as shown in Figure 14. This network creates a ramp voltage across C L , analogous to the ramp voltage generated across the ESR of a standard capacitor. This ramp is then capaci- tively coupled into the FB pin via capacitor C C . R1 R2 FB pin CC COUT L Low- side High- side CL RL Figure 14 — Virtual ESR Ramp Current The component values used in this circuit are calculated using the following procedure. Select C L (100nF) and R L to provide a 25mV ripple across C L (V CL ). CL OUT IN L I V V R where ON CL L CL T V C I and SW IN OUT ON f V V T Next choose a value for C C so that EQ ON C R T C where 2 1 2 1 EQ R R R R R The resistor values (R 1 and R 2 ) in the voltage divider circuit set the V OUT for the switcher. |
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