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LT6350CDDPBF датащи(PDF) 13 Page - Linear Technology |
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LT6350CDDPBF датащи(HTML) 13 Page - Linear Technology |
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13 / 28 page ![]() LT6350 13 6350f + – – + + – + – + – RS RG RF RINT RINT OUT1 OUT2 VIN V1 V2 VA +– –IN1 +IN1 +IN2 OP AMP 1 OP AMP 2 6350 F03 8 1 2 4 5 Figure 3. General Configuration Notice that the output common mode voltage is determined simply by the voltage at +IN2. However, since the voltage appliedat+IN2doesnotaffectthevoltageattheVOUT1output, a differential offset voltage will develop for VA = 0 when V1 does not equal V2. The value of the offset voltage will be 2 • (V1 – V2), as can be seen in Equation 2. For lowest differential offset, therefore, the input signal to pin +IN1, VIN, should be centered around the common mode voltage applied to pin +IN2. Often this voltage is provided by the ADC reference output. When the input is so centered and V1 = V2, Equation 2 reduces to: VOUTDIFF = 2 • VA • (1+RF/RG) The simple connection described in the Basic Connections section can be seen as a special case of the general circuit in Figure 3 where RF is a short circuit, RG is an open circuit, and the voltage at VIN is centered around the voltage V2. If differential gain greater than two is needed, the values of RF and RG can be adjusted in accordance with Equation (2). Additional information about feedback networks is given in the next section and in the Input Amplifier (Op Amp 1) Feedback Components section. Inverting Gain Connections/Interfacing to High Voltage Signals Although the previous examples have assumed the input signal is applied at +IN1, it is also possible to use the input op amp in an inverting configuration by fixing the voltage VIN and applying the input signal at V1 of Figure 3. Using the input op amp in the inverting configuration fixes its input common mode voltage at the voltage VIN, which allows the input signal at V1 to traverse a swing beyond the LT6350 supply rails. To avoid unwanted differential offsets in this configuration VIN should be chosen such that: VIN = V2/(1+(RF/RG)) Then Equation (1) reduces to: VOUTDIFF = –2 • V1 • (RF/RG)) Choosing RF = RG with the input at V1 leads to the gain of –2 configuration. A practical application for the inverting gain configuration is interfacing a high voltage op amp to a 5V differential SAR ADC.AsseeninFigure4,anindustrialapplicationmighthave OPERATION – + + – + – + – RF RG RINT RINT OUT1 OUTMAX OUTMIN OUT2 VIN V2 V2 OUTMAX OUTMIN OUTHV V2 OUTHVMAX OUTHVNOM OUTHVMIN –IN1 +IN1 +IN2 –15V +15V OP AMP 1 OP AMP 2 6350 F04 SIGNAL HIGH VOLTAGE OP AMP 8 1 2 5 4 Figure 4. Interfacing to High Voltage Signals sensed signals coming through an op amp running from ±15V rails. The LT6350 can easily interface the high voltage opamptoa5VADCbyusingtheinvertinggainconfiguration. For a clean interface, three conditions must be met: 1. VOUTDIFF = 0 when OUTHV is centered at OUTHVNOM. 2. VOUT1 = VOUTCM = V2 when OUTHV is centered at OUTHVNOM. 3. Full-scale signals at OUTHV are translated at the output of the LT6350 into the appropriate full-scale range for the ADC. Applying the above constraints to the design Equations (1) to (3) gives values for the ratio of RF to RG and for the value of VIN: R R OUT OUT OUT OUT V F G MAX MIN HVMAX HVMIN I /( )/( ) = −− N N F G HVNOM G F V R R OUT R R =+ + + 21 1 / ( ( / )) ( )/( ( / )) |
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