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LT1963 датащи(PDF) 19 Page - Linear Technology |
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LT1963 датащи(HTML) 19 Page - Linear Technology |
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19 / 28 page ![]() LT3089 19 3089f For more information www.linear.com/LT3089 APPLICATIONS INFORMATION For further information on thermal resistance and using thermal information, refer to JEDEC standard JESD51, notably JESD51-12. PCB layers, copper weight, board layout and thermal vias affect the resultant thermal resistance. Tables 3 through 5 provide thermal resistance numbers for best-case 4-layer boards with 1oz internal and 2oz external copper. Modern, multilayer PCBs may not be able to achieve quite the same level performance as found in these tables. Demo circuit 2318A’s board layout using multiple inner VOUT planes and multiple thermal vias achieves 17°C/W performance for the DF package. Calculating Junction Temperature Example: Given an output voltage of 0.9V, an IN voltage of 2.5V ±5%, output current range from 10mA to 0.8A and a maximum ambient temperature of 50°C, what is the maximum junction temperature for the DD-Pak on a 2500mm2 board with topside copper of 1000mm2? The power in the circuit equals: PTOTAL = (VIN – VOUT)(IOUT) The current delivered to the SET pin is negligible and can be ignored. VIN(MAX_CONTINUOUS) = 2.625V (2.5V + 5%) VOUT = 0.9V, IOUT = 0.8A, TA = 50°C Power dissipation under these conditions equals: PTOTAL = (VIN – VOUT)(IOUT) PTOTAL = (2.625V – 0.9V)(0.8A) = 1.38W Junction Temperature equals: TJ = TA + PTOTAL • θJA (using tables) TJ = 50°C + 1.38W • 14°C/W = 69.3°C In this case, the junction temperature is below the maxi- mum rating, ensuring reliable operation. Reducing Power Dissipation In some applications it may be necessary to reduce the powerdissipationintheLT3089packagewithoutsacrificing outputcurrentcapability.Twotechniquesareavailable.The first technique, illustrated in Figure 12, employs a resis- tor in series with the regulator’s input. The voltage drop across RS decreases the LT3089’s IN-to-OUT differential voltage and correspondingly decreases the LT3089’s power dissipation. Asanexample,assume:VIN=7V,VOUT=3.3VandIOUT(MAX) = 0.8A. Use the formulas from the Calculating Junction Temperature section previously discussed. Without series resistor RS, power dissipation in the LT3089 equals: PTOTAL = (7V – 3.3V) • 0.8A = 2.96W If the voltage differential (VDIFF) across the LT3089 is chosen as 1.5V, then RS equals: RS = 7V – 3.3V – 1.5V 0.8A = 2.8Ω Power dissipation in the LT3089 now equals: PTOTAL = 1.5V • 0.8A = 1.2W TheLT3089’spowerdissipationisnowonly40%compared to no series resistor. RSdissipates1.8Wofpower.Choose appropriate wattage resistors or use multiple resistors in parallel to handle and dissipate the power properly. 3089 F12 IN VIN′ SET OUT + – LT3089 50µA RSET RS VOUT VIN C2 C1 Figure 12. Reducing Power Dissipation Using a Series Resistor |
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