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PS2607 датащи(PDF) 16 Page - NEC |
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PS2607 датащи(HTML) 16 Page - NEC |
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16 / 38 page ![]() 15 ICBL ICBL-I1 RBE I1 VBE = ( 1 - ) ................ (5) As hFE' is equal to hFE if IF = approx. 5 mA, IC = approx. 15 mA, and RBC > 100 k Ω, expression (5) is simplified as follows: = 1 - ................ (6) IC' = hFE' (ICBL-I1) = hFE' ( ICBL- ) IC' = hFE' • ICBL ( 1 - ) ................ (4) Note IC' : Output current of an optocoupler having RBE hFE' : Amplification factor of an optocoupler having RBE Accordingly, the ratio of output current IC' (of the optocoupler having RBE) to output current IC (of the optocoupler with the base open) is expressed by: REDUCTION OF CURRENT TRANSFER RATIO (CTR) BY INSERTION OF BASE- EMITTER RESISTOR A resistor (RBE) connected to the base and emitter pins of an optocoupler causes the reduction of the output current (reduction of current transfer ratio). This is because a part (I1) of the base current flows through the base-emitter resistor and causes a voltage equivalent to the emitter-base voltage (VBE). The base current is reduced by this current component (I1) and, as the result, the current transfer ratio (CTR) goes down. The output current IC' is expressed as follows: VBE RBE ICBL • RBE VBE IC hFE ICBL • RBE IC' hFE' VBE IC ICBL • RBE IC' VBE Figure 3-2. • • • |
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