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LM4817 датащи(PDF) 15 Page - National Semiconductor (TI) |
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LM4817 датащи(HTML) 15 Page - National Semiconductor (TI) |
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15 / 21 page ![]() Application Information (Continued) AUDIO POWER AMPLIFIER DESIGN Audio Amplifier Design: Driving 1W into an 8 Ω Load The following are the desired operational parameters: Power Output: 1W RMS Load Impedance: 8 Ω Input Level: 1V RMS Input Impedance: 20k Ω Bandwidth: 100Hz−20 kHz ± 0.25 dB The design begins by specifying the minimum supply voltage necessary to obtain the specified output power. One way to find the minimum supply voltage is to use the Output Power vs Supply Voltage curve in the Typical Performance Char- acteristics section. Another way, using Equation (4), is to calculate the peak output voltage necessary to achieve the desired output power for a given load impedance. To ac- count for the amplifier’s dropout voltage, two additional volt- ages, based on the Dropout Voltage vs Supply Voltage in the Typical Performance Characteristics curves, must be added to the result obtained by Equation (8). The result in Equation (9). (8) V DD ≥ (V OUTPEAK +(VODTOP +VODBOT)) (9) The Output Power vs Supply Voltage graph for an 8 Ω load indicates a minimum supply voltage of 4.6V. This is easily met by the commonly used 5V supply voltage. The additional voltage creates the benefit of headroom, allowing the LM4817 to produce peak output power in excess of 1W without clipping or other audible distortion. The choice of supply voltage must also not create a situation that violates maximum power dissipation as explained above in the Power Dissipation section. After satisfying the LM4817’s power dissipation require- ments, the minimum differential gain is found using Equation (10). (10) Thus, a minimum gain of 2.83 allows the LM4817’s to reach full output swing and maintain low noise and THD+N perfor- mance. For this example, let A VD =3. The amplifier’s overall gain is set using the input (R i) and feedback (R f) resistors. With the desired input impedance set at 20k Ω, the feedback resistor is found using Equation (11). R f/Ri =AVD/2 (11) The value of R f is 30k Ω. The last step in this design example is setting the amplifier’s −3dB frequency bandwidth. To achieve the desired ±0.25dB pass band magnitude variation limit, the low frequency re- sponse must extend to at least one−fifth the lower bandwidth limit and the high frequency response must extend to at least five times the upper bandwidth limit. The gain variation for both response limits is 0.17dB, well within the ±0.25dB desired limit. The results are an f L = 100Hz/5 = 20Hz (12) and an F H = 20kHzx5 = 100kHz (13) As mentioned in the External Components section, R i and C i create a highpass filter that sets the amplifier’s lower bandpass frequency limit. Find the coupling capacitor’s value using Equation (14). (14) the result is 1/(2 π*20kΩ*20Hz) = 0.398µF (15) Use a 0.39µF capacitor, the closest standard value. The product of the desired high frequency cutoff (100kHz in this example) and the differential gain, A VD, determines the upper passband response limit. With A VD = 3 and fH = 100kHz, the closed-loop gain bandwidth product (GBWP) is 300kHz. This is less than the LM4817’s 3.5MHz GBWP. With this margin, the amplifier can be used in designs that require more differential gain while avoiding performance-lrestricting bandwidth limitations. LDO General Information Figure 2 shows the LM4817’s LDO functional block diagram. A 1.25V bandgap reference, an error amplifier and a PMOS pass transistor perform voltage regulation while being sup- ported by shutdown, fault, and the usual Temperature and current protection circuitry The regulator’s topology is the classic type with negative feedback from the output to one of the inputs of the error amplifier. Feedback resistors R 1 and R2 are either internal or external to the IC, depending on whether it is the fixed voltage version or the adjustable version. The negative feed- back and high open loop gain of the error amplifier cause the two inputs of the error amplifier to be virtually equal in voltage. If the output voltage changes due to load changes, the error amplifier provides the appropriate drive to the pass transistor to maintain the error amplifier’s inputs as virtually equal. In short, the error amplifier keeps the output voltage constant in order to keep its inputs equal. Output Voltage Setting The output voltage is set according to the amount of nega- tive feedback (Note that the pass transistor inverts the feed- back signal). Figure 3 simplifies the LDO’s topology. This 200781A0 FIGURE 2. LDO Functional Block Diagram www.national.com 15 |
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