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CS5166 датащи(PDF) 18 Page - Cherry Semiconductor Corporation |
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CS5166 датащи(HTML) 18 Page - Cherry Semiconductor Corporation |
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18 / 22 page ![]() Figure 25: 30A load waveforms. Figure 26: 15A load transient waveforms. Figure 26 shows supply response to a 15A load step with a 30A/µs slew rate. The V2 TM control loop immediately forces the duty cycle to 100%, ramping the current in both inductors up. A voltage spike of 136mV due to output capacitor impedance occurs. The inductive component of the spike due to ESL recovers within several microseconds. The resistive component due to ESR decreases as inductor current replaces capacitor current. The benefit of adaptive voltage positioning in reducing the voltage spike can readily be seen. The differences in DC voltage and duty cycle can also be observed. This particu- lar transient occurred near the beginning of regulator off- time, resulting in a longer recovery time and increased voltage spike. Output Inductor The inductor should be selected based on its inductance, current capability, and DC resistance. Increasing the induc- tor value will decrease output voltage ripple, but degrade transient response. Inductor Ripple Current Ripple current = Example: VIN = +5V, VOUT = +2.8V, ILOAD = 14.2A, L = 1.2µH, Freq = 200KHz Ripple current = = 5.1A Output Ripple Voltage VRIPPLE = Inductor Ripple Current × Output Capacitor ESR Example: VIN = +5V, VOUT = +2.8V, ILOAD = 14.2A, L = 1.2µH, Switching Frequency = 200KHz Output Ripple Voltage = 5.1A × Output Capacitor ESR (from manufacturer’s specs) ESR of Output Capacitors to limit Output Voltage Spikes ESR = This applies for current spikes that are faster than regula- tor response time. Printed Circuit Board resistance will add to the ESR of the output capacitors. In order to limit spikes to 100mV for a 14.2A Load Step, ESR = 0.1/14.2 = 0.007Ω Inductor Peak Current Peak Current = Maximum Load Current + () Example: VIN = +5V, VOUT = +2.8V, ILOAD = 14.2A, L = 1.2µH, Freq = 200KHz Peak Current = 14.2A + (5.1/2) = 16.75A A key consideration is that the inductor must be able to deliver the Peak Current at the switching frequency with- out saturating. Response Time to Load Increase (limited by Inductor value unless Maximum On-Time is exceeded) Response Time = Example: VIN = +5V, VOUT = +2.8V, L = 1.2µH, 14.2A change in Load Current Response Time = = 7.7µs 1.2µH × 14.2A (5V-2.8V) L × ∆ IOUT (VIN-VOUT) Ripple Current 2 ∆ VOUT ∆ IOUT [(5V-2.8V) × 2.8V] [200KHz × 1.2µH × 5V] [(VIN - VOUT) × VOUT] (Switching Frequency × L × VIN) Trace 1 Output voltage ripple Trace 2 Buck regulator #1 inductor switching node Trace 3 Buck regulator #2 inductor switching node Trace 1 Output voltage ripple Trace 2 Buck regulator #1 inductor switching node Trace 3 Buck regulator #2 inductor switching node Application Information: continued 18 |
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