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MP24971DN датащи(PDF) 10 Page - Monolithic Power Systems |
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MP24971DN датащи(HTML) 10 Page - Monolithic Power Systems |
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10 / 14 page ![]() MP24971 –1.5A, 50V, 100kHz, 5V FIXED OUTPUT STEP-DOWN CONVERTER MP24971 Rev. 1.01 www.MonolithicPower.com 10 1/6/2012 MPS Proprietary Information. Patent Protected. Unauthorized Photocopy and Duplication Prohibited. © 2012 MPS. All Rights Reserved. APPLICATION INFORMATION Setting the Output Line Drop Compensation Long traces to the circuit load induce a voltage drop between VOUT and VLOAD. that can be described as: DROP OUT TRACE VI R (1) Where TRACE TRACE1 TRACE2 RR R as seen in Figure 2. Then, the VLOAD is: LOAD OUT OUT TRACE VV I R (2) Supplying an accurate and consistent load voltage over current-dependant trace resistance necessitates line-drop compeonsation. MP24971 offers a compensation method that adjusts the FB voltage slightly according to the load current. The relation between VOUT and VFB can be described by: OUT FB OUT SENSE FB TOP BOT C VV I R 6 V RR R (3) Where, VFB is 0.8V. Then, the VOUT can be calculated by: OUT SENSE TOP OUT C IR 6 R V5V R (4) The VLOAD is determined by: OUT SENSE TOP LOAD C OUT TRACE IR 6 R V5V R IR (5) To maintain a VLOAD that is not variable with load current, balance the equation below: OUT SENSE TOP OUT TRACE C IR 6 R IR R (6) Where RTOP is 300kΩ. Simplifying, we find that RC comes out to: SENSE C TRACE R6 300k R R (7) Where RSENSE is known and RTRACE can be tested or evaluated SW ISP ISN RSENSE 0.8V VOS Load VOUT ERROR AMPLIFIER RTOP RBOT 600mV X 6 Hiccup Current Limit 10000kO 10pF Internal Block RTRACE RTRACE1 RTRACE2 VOC RC VFB VLOAD Figure 2—Output Line Drop Compensation Selecting the Inductor For most applications, use a 10µH to 47µH inductor with a DC current rating of at least 125% of the maximum load current. For best efficiency, select an inductor with a DC resistance less than 200mΩ. For most designs, the inductance value can be determined by. OSC L IN OUT IN OUT f I V ) V V ( V L (8) Where ΔIL is the inductor ripple current. Choose inductor current ripple to equal approximately 30% of the maximum load current, 1.5A. Then maximum inductor peak current is: 2 I I I L LOAD ) MAX ( L (9) Under light-load conditions below 100mA, use a larger inductor to improve efficiency. |
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