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ST466PJD датащи(PDF) 2 Page - Coilcraft lnc.

номер детали ST466PJD
подробное описание детали  Coupled Inductors for Critical Applications
PDF  3 Pages
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производитель  COILCRAFT [Coilcraft lnc.]
домашняя страница  http://www.coilcraft.com
Logo COILCRAFT - Coilcraft lnc.

ST466PJD датащи(HTML) 2 Page - Coilcraft lnc.

  ST466PJD Datasheet HTML 1Page - Coilcraft lnc. ST466PJD Datasheet HTML 2Page - Coilcraft lnc. ST466PJD Datasheet HTML 3Page - Coilcraft lnc.  
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ST466PJDSeriesCoupledInductors
®
© Coilcraft, Inc. 2012
1102 Silver Lake Road
Cary, IL 60013
Phone 800-981-0363
Fax 847-639-1508
Email cps@coilcraft.com
www.coilcraft-cps.com
This product may not be used in medical or high
risk applications without prior Coilcraft approval.
Specifications subject to change without notice.
Please check our web site for latest information.
5030 COUPLED INDUCTORS
Document ST757-2 Revised 09/06/12
Coupling
Leakage
Isat (A)6
Irms (A)
Inductance2 DCR max3 SRF typ4 coefficient
L typ5
10%
20%
30%
both
one
Part number1
(µH)
(Ohms)
(MHz)
typ
(µH)
drop
drop
drop
windings7 winding8
ST466PJD102NLZ
1.0 ±30%
0.042
156
0.95
0.09
4.6
4.8
5.0
2.60
3.68
ST466PJD152MLZ
1.5 ±20%
0.048
123
0.97
0.09
3.9
4.2
4.3
2.20
3.11
ST466PJD222MLZ
2.2 ±20%
0.067
78.0
0.98
0.10
3.1
3.3
3.4
2.15
3.04
ST466PJD332MLZ
3.3 ±20%
0.077
65.0
0.98
0.10
2.5
2.7
2.8
1.85
2.62
ST466PJD472MLZ
4.7 ±20%
0.111
53.0
0.99
0.11
2.1
2.2
2.2
1.45
2.05
ST466PJD562MLZ
5.6 ±20%
0.125
48.0
0.99
0.11
2.0
2.0
2.1
1.35
1.91
ST466PJD682MLZ
6.8 ±20%
0.159
43.0
0.99
0.12
1.8
1.9
1.9
1.20
1.70
ST466PJD103MLZ
10 ±20%
0.210
31.0
0.99
0.13
1.3
1.3
1.3
1.05
1.48
ST466PJD153MLZ
15 ±20%
0.298
25.0
0.99
0.15
1.2
1.4
1.4
0.85
1.20
ST466PJD223MLZ
22 ±20%
0.452
19.0
1.0
0.17
1.0
1.1
1.1
0.70
0.99
ST466PJD333MLZ
33 ±20%
0.565
15.0
1.0
0.20
0.80
0.84
0.85
0.60
0.85
ST466PJD473MLZ
47 ±20%
0.806
12.6
1.0
0.24
0.65
0.69
0.72
0.50
0.71
ST466PJD683MLZ
68 ±20%
1.13
10.0
1.0
0.29
0.50
0.54
0.55
0.46
0.64
ST466PJD104MLZ
100 ±20%
1.79
8.32
1.0
0.37
0.47
0.54
0.56
0.35
0.49
ST466PJD154MLZ
150 ±20%
2.43
6.80
1.0
0.46
0.38
0.43
0.45
0.31
0.43
ST466PJD224MLZ
220 ±20%
3.30
5.55
1.0
0.54
0.31
0.35
0.36
0.26
0.37
ST466PJD334MLZ
330 ±20%
5.36
4.05
1.0
0.65
0.25
0.25
0.32
0.20
0.28
ST466PJD474MLZ
470 ±20%
7.51
3.34
1.0
0.76
0.21
0.24
0.26
0.17
0.23
ST466PJD684MLZ
680 ±20%
10.8
2.78
1.0
0.89
0.17
0.20
0.21
0.14
0.19
ST466PJD105MLZ
1000 ±20%
16.5
2.24
1.0
1.20
0.15
0.17
0.17
0.11
0.15
1. When ordering, please specify
termination and testing code:
ST466PJD105MLZ
Termination: L = RoHS compliant silver-palladium-platinum-glass frit.
Special order:
T = RoHS tin-silver-copper (95.5/4/0.5)
or
S = non-RoHS tin-lead (63/37).
Testing:
Z = COTS
H = Screening per Coilcraft CPSA-10001
2. Inductance shown for each winding, measured at 100 kHz, 0.1 Vrms,
0 Adc on an Agilent/HP 4284A LCR meter or equivalent. When leads
are connected in parallel, inductance is the same value. When leads are
connected in series, inductance is four times the value.
3. DCR is for each winding. When leads are connected in parallel, DCR
is half the value. When leads are connected in series, DCR is twice the
value.
4. SRF measured using an Agilent/HP 4191A or equivalent. When leads
are connected in parallel, SRF is the same value.
5. Leakage Inductance is for L1 and is measured with L2 shorted.
6. DC current, at which the inductance drops the specified amount from its
value without current. It is the sum of the current flowing in both windings.
7. Equal current when applied to each winding simultaneously that causes
a 40°C temperature rise from 25°C ambient. See temperature rise
calculation.
8. Maximum current when applied to one winding that causes a 40°C
temperature rise from 25°C ambient. See temperature rise calculation.
9. Electrical specifications at 25°C.
Temperature rise calculation based on specified Irms
Temperature rise = Winding power loss × 90°C
W
Winding power loss = (+
) × DCR in Watts (W)
II
L1
2
L2
2
Equal current in each winding (1.4 A):
Winding power loss = (1.4 + 1.4 ) × 0.111 = 0.435 W
Temperature rise = 0.435 W × 90°C
W
= 39.2°C
22
Unequal current (II
L1
L2
ower loss = (1.8 + 0.8 ) × 0.111 = 0.431 W
Temperature rise = 0.431 W × 90°C
W
= 38.8°C
22
= 1.8 A,
= 0.8 A):
Winding p
Examples for ST466PJB472ML:



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