Rev. 0.1 / November 2008

39

H5PS2G43AFR

H5PS2G83AFR

tracting 0.02 x tCK (avg) from it, whereas if an input clock has a worst case tCH (avg) of 0.52, the tAOF,

max should be derated by adding 0.02 x tCK (avg) to it. Therefore, we have;

tAOF, min (derated) = tAC, min - [0.5 - Min(0.5, tCH (avg), min)] x tCK (avg)

tAOF, max (derated) = tAC, max + 0.6 + [Max(0.5, tCH (avg), max) - 0.5] x tCK (avg)

or

tAOF, min (derated) = Min (tAC, min, tAC, min - [0.5 - tCH (avg), min] x tCK (avg))

tAOF, max (derated) = 0.6 + Max (tAC, max, tAC, max + [tCH (avg), max - 0.5] x tCK (avg))

where tCH (avg), min and tCH (avg), max are the minimum and maximum of tCH (avg) actually measured

at the DRAM input balls.

Note that these deratings are in addition to the tAOF derating per input clock jitter, i.e. tJIT (duty) and

tERR(6-10per). However tAC values used in the equations shown above are from the timing parameter

table and are not derated. Thus the final derated values for tAOF are;

tAOF, min (derated_final) = tAOF, min (derated) + {- tJIT (duty), max - tERR(6-10per),max}

tAOF, max (derated_final) = tAOF, max (derated) + {- tJIT (duty), min - tERR(6-10per),min}