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LT1057SW датащи(PDF) 8 Page - Linear Technology

номер детали LT1057SW
подробное описание детали  Dual and Quad, JFET Input Precision High Speed Op Amps
PDF  16 Pages
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производитель  LINER [Linear Technology]
домашняя страница  http://www.linear.com
Logo LINER - Linear Technology

LT1057SW датащи(HTML) 8 Page - Linear Technology

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LT1057/LT1058
8
10578fc
TYPICAL PERFORMANCE CHARACTERISTICS
Common Mode Rejection Ratio
vs Frequency
Common Mode Range
vs Temperature
Common Mode and Power Supply
Rejections vs Temperature
Power Supply Rejection Ratio
vs Frequency
Supply Current
vs Temperature
Short-Circuit Current vs Time
(One Output Shorted to Ground)
The LT1057 may be inserted directly in LF353, LF412,
LF442, TL072, TL082 and OP-215 sockets. The LT1058
plugs into LF347, LF444, TL074 and TL084 sockets. Of
course, all standard dual and quad bipolar op amps can
also be replaced by these devices.
High Speed Operation
When the feedback around the op amp is resistive (RF)
a pole will be created with RF, the source resistance and
capacitance (RS, CS), and the amplifier input capacitance
(CIN ≈ 4pF). In low closed loop gain configurations and
APPLICATIONS INFORMATION
with RS and RF in the kilohm range, this pole can create
excess phase shift and even oscillation. A small capaci-
tor (CF) in parallel with RF eliminates this problem. With
RS(CS + CIN) = RFCF, the effect of the feedback pole is
completely removed.
OUTPUT
–
+
CIN
RF
RS
CF
CS
10578 F01
FREQUENCY (Hz)
10
0
20
40
60
80
120
100
1k
10k
100k
10578 G19
1M
10M
100
VS = 15V
TA = 25°C
TEMPERATURE (°C)
–50
–15
–14
–12
–11
10
15
12
0
50
10578 G20
–13
13
14
11
100
VS = 15V
TEMPERATURE (°C)
110
120
25
75
10578 G21
100
–25
125
PSRR
CMRR
90
VS = 10V TO 17V FOR PSRR
VS = 15V, VCM = 10.5V FOR CMRR
FREQUENCY (Hz)
10
140
120
100
80
60
40
20
0
10k
1M
10578 G22
100
1k
100k
10M
TA = 25°C
POSITIVE
SUPPLY
NEGATIVE
SUPPLY
TEMPERATURE (°C)
–50
2
3
25
75
10578 G23
1
–25
0
50
100
125
0
VS = 15V
VS = 10V
TIME FROM OUTPUT SHORT TO GROUND (MINUTES)
0
–50
–40
–20
–10
0
50
20
1
2
10578 G24
–30
30
40
10
3
TA = –55°C
TA = 25°C
TA = 125°C
TA = 125°C
TA = 25°C
TA = –55°C
VS = 15V



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