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HA17431FP датащи(PDF) 16 Page - Renesas Technology Corp |
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HA17431FP датащи(HTML) 16 Page - Renesas Technology Corp |
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16 / 20 page ![]() HA17431 Series REJ03D0678-0300 Rev.3.00 Apr 03, 2007 Page 16 of 19 In Figure 3, the following formulas are obtained: Gain G1 = G0 ≈ 50 dB to 60 dB (determined by shunt regulator) G2 = R5 R3 Corner frequencies f1 = 1/(2π C1 G0 R3) f2 = 1/(2π C1 R5) G0 is the shunt regulator open-loop gain; this is given by the reciprocal of the reference voltage fluctuation ∆Vref/∆V KA, and is approximately 50 dB. 3. Practical Example Consider the example of a photocoupler, with an internal light emitting diode VF = 1.05 V and IF = 2.5 mA, power supply output voltage V2 = 5 V, and bias resistance R2 current of approximately 1/5 IF at 0.5 mA. If the shunt regulator VK = 3 V, the following values are found. R1 = 5V – 1.05V – 3V 2.5mA + 0.5mA = 316( Ω) (330Ω from E24 series) R2 = 1.05V 0.5mA = 2.1(k Ω) (2.2kΩ from E24 series) Next, assume that R3 = R4 = 10 kΩ. This gives a 5 V output. If R5 = 3.3 kΩ and C1 = 0.022 µF, the following values are found. G2 = 3.3 kΩ / 10 kΩ = 0.33 times (–10 dB) f1 = 1 / (2 × π × 0.022 µF × 316 × 10 kΩ) = 2.3 (Hz) f2 = 1 / (2 × π × 0.022 µF × 3.3 kΩ) = 2.2 (kHz) |
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