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LM2694 датащи(PDF) 13 Page - National Semiconductor (TI)

[Old version datasheet] Texas Instruments acquired National semiconductor. Click here to check the latest version.
номер детали LM2694
подробное описание детали  30V, 600 mA Step Down Switching Regulator
PDF  19 Pages
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производитель  NSC [National Semiconductor (TI)]
домашняя страница  http://www.national.com
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LM2694 датащи(HTML) 13 Page - National Semiconductor (TI)

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Applications Information (Continued)
F
S = 250 kHz
Minimum load current = 100 mA
Maximum load current = 600 mA
Softstart time=5ms.
R1 and R2: These resistors set the output voltage, and their
ratio is calculated from:
R1/R2 = (V
OUT/2.5V) - 1
(7)
R1/R2 calculates to 1.0. The resistors should be chosen
from standard value resistors in the range of 1.0 k
Ω -10kΩ.
A value of 2.5 k
Ω will be used for R1 and for R2.
R
ON,FS: RON can be chosen using Equation 5 to set the
nominal frequency, or from Equation 4 if the on-time at a
particular V
IN is important. A higher frequency generally
means a smaller inductor and capacitors (value, size and
cost), but higher switching losses. A lower frequency means
a higher efficiency, but with larger components. Generally, if
PC board space is tight, a higher frequency is better. The
resulting on-time and frequency have a ±25% tolerance.
Using equation 5 at a V
IN of 8V,
A value of 140 k
Ω will be used for R
ON, yielding a nominal
frequency of 252 kHz.
L1: The guideline for choosing the inductor value in this
example is that it must keep the circuit’s operation in con-
tinuous conduction mode at minimum load current. This is
not a strict requirement since the LM2694 regulates correctly
when in discontinuous conduction mode, although at a lower
frequency. However, to provide an initial value for L1 the
above guideline will be used.
To keep the circuit in continuous conduction mode, the maxi-
mum allowed ripple current is twice the minimum load cur-
rent, or 200 mAp-p. Using this value of ripple current, the
inductor (L1) is calculated using the following:
(8)
where F
S(min) is the minimum frequency of 189 kHz (252 kHz
- 25%).
This provides a minimum value for L1 - the next higher
standard value (150 µH) will be used. To prevent saturation,
and possible destructive current levels, L1 must be rated for
the peak current which occurs if the current limit and maxi-
mum ripple current are reached simultaneously. The maxi-
mum ripple amplitude is calculated by re-arranging Equation
8 using V
IN(max),FS(min), and the minimum inductor value,
based on the manufacturer’s tolerance. Assume, for this
exercise, the inductor’s tolerance is ±20%.
(9)
I
PK =ILIM +IOR(max) = 0.74A + 0.18A = 0.92A
where I
LIM is the maximum guaranteed current limit thresh-
old. At the nominal maximum load current of 0.6A, the peak
inductor current is 692 mA.
C1: This capacitor limits the ripple voltage at VIN resulting
from the source impedance of the supply feeding this circuit,
and the on/off nature of the switch current into VIN. At
maximum load current, when the buck switch turns on, the
current into VIN steps up from zero to the lower peak of the
inductor current waveform (I
PK- in Figure 12), ramps up to
the peak value (I
PK+), then drops to zero at turn-off. The
average current into VIN during this on-time is the load
current. For a worst case calculation, C1 must supply this
average current during the maximum on-time. The maximum
on-time is calculated at V
IN = 8V using Equation 4, with a
25% tolerance added:
The voltage at VIN should not be allowed to drop below 7.5V
in order to maintain V
CC above its UVLO.
20187037
FIGURE 12. Inductor Current
www.national.com
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