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LTM4650A датащи(PDF) 21 Page - Analog Devices

номер детали LTM4650A
подробное описание детали  Quad DC/DC 關Module Regulator with Configurable Dual 12A, Dual 5A Output Array
PDF  36 Pages
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производитель  AD [Analog Devices]
домашняя страница  http://www.analog.com
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LTM4671
21
Rev. B
For more information www.analog.com
where T is the diode junction temperature in Kelvin, q is
the electron charge and k is Boltzmann’s constant. VT is
approximately 26mV at room temperature (298K) and
scales linearly with Kelvin temperature. It is this linear
temperature relationship that makes diodes suitable tem-
perature sensors. The IS term in the previous equation is
the extrapolated current through a diode junction when
the diode has zero volts across the terminals. The IS term
varies from process to process, varies with temperature,
and by definition must always be less than ID. Combining
all of the constants into one term:
KD =
η • k
q
where KD = 8.62−5, and knowing ln(ID/IS) is always posi-
tive because ID is always greater than IS, leaves us with
the equation that:
VD = T KELVIN
(
)•KD •In
ID
IS
where VD appears to increase with temperature. It is com-
mon knowledge that a silicon diode biased with a current
source has an approximate –2mV/°C temperature rela-
tionship (Figure 7), which is at odds with the equation. In
fact, the IS term increases with temperature, reducing the
ln(ID/IS) absolute value yielding an approximate –2mV/°C
composite diode voltage slope.
To obtain a linear voltage proportional to temperature
we cancel the IS variable in the natural logarithm term to
remove the IS dependency from the equation 1. This is
accomplished by measuring the diode voltage at two cur-
rents I1, and I2, where I1 = 10 • I2) and subtracting we get:
∆VD = T(KELVIN)•KD •IN
I1
IS
– T(KELVIN)•KD •IN
I2
IS
Combining like terms, then simplifying the natural log
terms yields:
∆VD = T(KELVIN) • KD • lN(10)
and redefining constant
K'D = KD •IN(10) =
198µV
K
yields
∆VD = K’D • T(KELVIN)
Solving for temperature:
T(KELVIN) =
∆VD
K'D
(°CELSIUS) = T(KELVIN)– 273.15
where
300°K = 27°C
means that is we take the difference in voltage across the
diode measured at two currents with a ratio of 10, the
resulting voltage is 198μV per Kelvin of the junction with
a zero intercept at 0 Kelvin.
The diode connected NPN transistor across the TSENSEn+
and pin and TSENSEn− pins can be used to monitor the
internal temperature of the LTM4671 channel 0 and 3.
The 5A Channels (CH1, CH2):
The LTM4671 produces a voltage at the TMON pin
proportional to the measured junction temperature. The
junction temperature-to-voltage scaling factor is 200°K/V.
Thus, to obtain the junction temperature in degrees Kelvin,
simply multiply the voltage provided at the TMON pin by
the scaling factor. To obtain the junction temperature in
degrees Celsius, subtract 273 from the value obtained in
degrees Kelvin.
TEMPERATURE (°C)
–50 –25
0.3
0.5
0.8
0
50
75
0.4
0.7
0.6
25
100
4671 F07
125
Figure 7. Diode Voltage VD vs Temperature T(°C)
APPLICATIONS INFORMATION



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