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LM4940 датащи(PDF) 11 Page - National Semiconductor (TI)

[Old version datasheet] Texas Instruments acquired National semiconductor. Click here to check the latest version.
номер детали LM4940
подробное описание детали  6W Streo Audio Power Amplifier
PDF  14 Pages
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производитель  NSC [National Semiconductor (TI)]
домашняя страница  http://www.national.com
Logo NSC - National Semiconductor (TI)

LM4940 датащи(HTML) 11 Page - National Semiconductor (TI)

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Application Information (Continued)
C
B (µF)
T
ON (ms)
1.0
120
2.2
120
4.7
200
10
440
In order eliminate "clicks and pops", all capacitors must be
discharged before turn-on. Rapidly switching V
DD may not
allow the capacitors to fully discharge, which may cause
"clicks and pops".
There is a relationship between the value of C
IN
and
C
BYPASS that ensures minimum output transient when power
is applied or the shutdown mode is deactivated. Best perfor-
mance is achieved by setting the time constant created by
C
IN and Ri +Rf to a value less than the turn-on time for a
given value of C
BYPASS as shown in the table above.
AUDIO POWER AMPLIFIER DESIGN
Audio Amplifier Design: Driving 3W into a 4
Ω load
The following are the desired operational parameters:
Power Output
3W
RMS
Load Impedance
4
Ω
Input Level
0.3V
RMS (max)
Input Impedance
20k
Ω
Bandwidth
100Hz–20kHz ± 0.25dB
The design begins by specifying the minimum supply voltage
necessary to obtain the specified output power. One way to
find the minimum supply voltage is to use the Output Power
vs Power Supply Voltage curve in the Typical Performance
Characteristics section. Another way, using Equation (8), is
to calculate the peak output voltage necessary to achieve
the desired output power for a given load impedance. To
account for the amplifier’s dropout voltage, two additional
voltages, based on the Clipping Dropout Voltage vs Power
Supply Voltage in the Typical Performance Characteris-
tics curves, must be added to the result obtained by Equa-
tion (8). The result is Equation (9).
(6)
V
DD =VOUTPEAK +VODTOP +VODBOT
(7)
The Output Power vs. Power Supply Voltage graph for an 8
Ω
load indicates a minimum supply voltage of 11.8V. The com-
monly used 12V supply voltage easily meets this. The addi-
tional voltage creates the benefit of headroom, allowing the
LM4940 to produce an output power of 3W without clipping
or other audible distortion. The choice of supply voltage must
also not create a situation that violates of maximum power
dissipation as explained above in the Power Dissipation
section. After satisfying the LM4940’s power dissipation re-
quirements, the minimum differential gain needed to achieve
3W dissipation in a 4
Ω BTL load is found using Equation
(10).
(8)
Thus, a minimum gain of 11.6 allows the LM4940’s to reach
full output swing and maintain low noise and THD+N perfor-
mance. For this example, let A
V = 12. The amplifier’s overall
BTL gain is set using the input (RIN
A) and feedback (R)
resistors of the first amplifier in the series BTL configuration.
Additionaly, A
V-BTL is twice the gain set by the first amplifier’s
R
IN and Rf. With the desired input impedance set at 20k
Ω,
the feedback resistor is found using Equation (11).
R
f / RIN =AV
(9)
The value of R
f is 240k
Ω. The nominal output power is 3W.
The last step in this design example is setting the amplifier’s
-3dB frequency bandwidth. To achieve the desired ±0.25dB
pass band magnitude variation limit, the low frequency re-
sponse must extend to at least one-fifth the lower bandwidth
limit and the high frequency response must extend to at least
five times the upper bandwidth limit. The gain variation for
both response limits is 0.17dB, well within the ±0.25dB-
desired limit. The results are an
f
L = 100Hz/5= 20Hz
(10)
and an
f
L = 20kHzx5= 100kHz
(11)
As mentioned in the SELECTING EXTERNAL COMPO-
NENTS section, R
INA and CINA, as well as COUT and RL,
create a highpass filter that sets the amplifier’s lower band-
pass frequency limit. Find the coupling capacitor’s value
using Equation (14).
C
IN =1 / 2
πR
INfL
(12)
The result is
1 / (2
πx20kΩx20Hz) = 0.398µF = C
IN
and
1 / (2
πx4Ωx20Hz) = 1989µF = C
OUT
Use a 0.39µF capacitor for C
IN and a 2000µF capacitor for
C
OUT, the closest standard values.
The product of the desired high frequency cutoff (100kHz in
this example) and the differential gain A
V, determines the
upper passband response limit. With A
V = 12 and fH =
100kHz, the closed-loop gain bandwidth product (GBWP) is
1.2mHz. This is less than the LM4940’s 3.5MHz GBWP. With
this margin, the amplifier can be used in designs that require
more differential gain while avoiding performance restricting
bandwidth limitations.
www.national.com
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